document.write( "Question 1001602: Write an equation:\r
\n" ); document.write( "\n" ); document.write( "Vertex is (5,4)\r
\n" ); document.write( "\n" ); document.write( "Focus is (8,4)
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Algebra.Com's Answer #618725 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Write an equation of the parabola with vertex (3, 1) and focus (3, 5).\r
\n" ); document.write( "\n" ); document.write( " Write an equation:
\n" ); document.write( "Vertex is (\"5\",\"4\")
\n" ); document.write( "Focus is (\"8\",\"4\") \r
\n" ); document.write( "\n" ); document.write( "The equation of a parabola with vertex (\"h\",\"k\") is either\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+h%29%5E2+=+4p%28y+-+k%29+\"\r
\n" ); document.write( "\n" ); document.write( "or
\n" ); document.write( "\"%28y+-+k%29%5E2+=+4p%28x+-+h%29\"\r
\n" ); document.write( "\n" ); document.write( "where the vertex is (\"h\",\"k\"), \"p\" is distance from vertex to focus \r
\n" ); document.write( "\n" ); document.write( "Since the vertex is (\"5\",\"4\"), \"h+=+5\" and \"k+=+4\".\r
\n" ); document.write( "\n" ); document.write( "Since the vertex (\"5\",\"4\") and focus (\"8\",\"4\") have the same y-coordinate, it is equation of the second type.\r
\n" ); document.write( "\n" ); document.write( "\"%28y+-+k%29%5E2+=+4p%28x+-+h%29\"\r
\n" ); document.write( "\n" ); document.write( "The distance from vertex to focus is \"3\" units. Since the focus is right of the vertex, \"p\" is positive, and so \"p+=+3\". (Parabola opens to the right)\r
\n" ); document.write( "\n" ); document.write( "So the equation is\r
\n" ); document.write( "\n" ); document.write( "\"%28y+-+4%29%5E2+=+4%2A3%28x+-+5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y+-+4%29%5E2+=+12%28x+-+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y+-+4%29%5E2%2F12+=+x+-+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F12%29%28y+-+4%29%5E2%2B5+=+x+\"\r
\n" ); document.write( "\n" ); document.write( "it cannot be this:
\n" ); document.write( "x= 1/4c y^2 (x-h)^2 + k....here is something wrong\r
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