document.write( "Question 1001509: Please tell me if my process is right or wrong.\r
\n" ); document.write( "\n" ); document.write( "lim x->-∞ √(6x^6-1)/(5x^3+1)\r
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\n" ); document.write( "\n" ); document.write( "for this since it's infinity then -1 and +1 can be disregarded. And therefore I am left with:\r
\n" ); document.write( "\n" ); document.write( "lim x->-∞ √(6x^6)/(5x^3)\r
\n" ); document.write( "\n" ); document.write( "The part I don't remember is an algebra rule, when we sqrt the 6x^6 do we break them up or take them together? I think we take them as separate terms 6 and x^6 if so then it's:\r
\n" ); document.write( "\n" ); document.write( "lim x->-∞ (√(6)√(x^6))/(5x^3)\r
\n" ); document.write( "\n" ); document.write( "then nothing happens to the √(6), however, another rule I forget is when you squareroot something this is the same as (x^6)^(1/2) right? so then it becomes x^3 however, why does this become an absolute number like so |x^3| I don't remember this rule at all. When you squareroot something whatever it is that becomes absolute?\r
\n" ); document.write( "\n" ); document.write( "Then the problem becomes:\r
\n" ); document.write( "\n" ); document.write( "lim x->-∞ √(6)*|x^3| / (5x^3)
\n" ); document.write( "then
\n" ); document.write( "lim x->-∞ √(6)*|-∞^3| / (5(-∞)^3)\r
\n" ); document.write( "\n" ); document.write( "since its abs value w/e the value is it will be positive. therefore:
\n" ); document.write( "lim x->-∞ √(6)(∞)^3/(5(-∞)^3)\r
\n" ); document.write( "\n" ); document.write( "so the ∞'s cancel to be -1 and the √(6)/5 remain constant.\r
\n" ); document.write( "\n" ); document.write( "lim x->-∞ - √(6)/5\r
\n" ); document.write( "\n" ); document.write( "Please explain out the algebra confusion\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #618680 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The output of the numerator is always positive.
\n" ); document.write( "The domain is limited because of the square root.
\n" ); document.write( "\"6x%5E6-1%3E=0\"
\n" ); document.write( "\"x%5E6%3E=1%2F6\"
\n" ); document.write( "\"x%3E=1%2F6%5E%281%2F6%29\" and \"x%3C=-1%2F6%5E%281%2F6%29\"
\n" ); document.write( "So when,
\n" ); document.write( "\"x%3E=1%2F6%5E%281%2F6%29\", the denominator is positive, so when \"x\" heads towards \"infinity\", the function value heads to \"sqrt%286%29%2F5\"
\n" ); document.write( "and when,
\n" ); document.write( "\"x%3C=-1%2F6%5E%281%2F6%29\", the denominator is negative, so when \"x\" heads towards \"-infinity\", the function values heafs to \"-sqrt%286%29%2F5\"
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