document.write( "Question 1001229: A computer has 100 components. The probability that a component will fail is 0.0022. Assuming that the components function independently, what is the probability that between 1 and 3 components will fail??\r
\n" ); document.write( "\n" ); document.write( "Confused as to how to even start this question. An explanation of the solution would be greatly appreciated!
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Algebra.Com's Answer #618657 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The probability of failure can be modeled as a function of the number of components that fail,
\n" ); document.write( "\"P%28x%29=C%28100%2Cx%29%2A%281-0.0022%29%5E%28100-x%29%280.0022%29%5E%28x%29\"
\n" ); document.write( "So for between 1 and 3 components failing calculate \"P%281%29\", \"P%282%29\", and \"P%283%29\" and sum the probabilities.
\n" ); document.write( "\"C%28100%2C1%29=100\"
\n" ); document.write( "\"C%28100%2C2%29=4950\"
\n" ); document.write( "\"C%28100%2C3%29=161700\"
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\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "\"P%281%29=+100%2A%280.9978%29%5E99%2A%280.0022%29%5E1+=0.1769\"
\n" ); document.write( "\"P%282%29=+4950%2A%280.9978%29%5E98%2A%280.0022%29%5E2+=0.01931\"
\n" ); document.write( "\"P%283%29=+161700%2A%280.9978%29%5E97%2A%280.0022%29%5E3+=0.001391\"\r
\n" ); document.write( "\n" ); document.write( "So then,
\n" ); document.write( "\"P=0.1769%2B0.01931%2B0.001391\"
\n" ); document.write( "\"P=0.1976\"
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