document.write( "Question 1001515: Simplify the expression
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Algebra.Com's Answer #618650 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
(3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)!\r
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\n" ); document.write( "\n" ); document.write( "the (3n-3)! in the numerator and denominator cancel out and you are left with:\r
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\n" ); document.write( "\n" ); document.write( "(3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "let n = 7\r
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\n" ); document.write( "\n" ); document.write( "3n+2 = 23
\n" ); document.write( "3n+1 = 22
\n" ); document.write( "3n+0 = 21
\n" ); document.write( "3n-1 = 20
\n" ); document.write( "3n-2 = 19
\n" ); document.write( "3n-3 = 18\r
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\n" ); document.write( "\n" ); document.write( "(3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)! which becomes:
\n" ); document.write( "23! / 18! = (23 * 22 * 21 * 20 * 19 * 18! divided by 18! which becomes:
\n" ); document.write( "(23 * 22 * 21 * 20 * 19)\r
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\n" ); document.write( "\n" ); document.write( "the result is 4037880\r
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\n" ); document.write( "\n" ); document.write( "i used my ti-84 to take 23! and divide it by 18! and i got 4037880.\r
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\n" ); document.write( "\n" ); document.write( "this confirms the solution is correct.\r
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