document.write( "Question 1001515: Simplify the expression
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document.write( "(3n+2)!/(3n-3)! \n" );
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Algebra.Com's Answer #618650 by Theo(13342)![]() ![]() You can put this solution on YOUR website! (3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the (3n-3)! in the numerator and denominator cancel out and you are left with:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let n = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3n+2 = 23 \n" ); document.write( "3n+1 = 22 \n" ); document.write( "3n+0 = 21 \n" ); document.write( "3n-1 = 20 \n" ); document.write( "3n-2 = 19 \n" ); document.write( "3n-3 = 18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)! which becomes: \n" ); document.write( "23! / 18! = (23 * 22 * 21 * 20 * 19 * 18! divided by 18! which becomes: \n" ); document.write( "(23 * 22 * 21 * 20 * 19)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the result is 4037880\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i used my ti-84 to take 23! and divide it by 18! and i got 4037880.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the solution is correct.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |