document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001511>Question 1001511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I truly see why people say it's not the calculus that trips people up, it's the algebra....\r<BR>\n" );
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document.write( "Let f(x) = x^(5/3) + 5x^(2/3)\r<BR>\n" );
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document.write( "f'(x) = (5/3)x^(2/3) + (10/3)x^(-1/3) = 0\r<BR>\n" );
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document.write( "someone told me you can factor out an x^(1/3) but how does that work when there is 5/3x and 10/3 there and ones an exponent of (2/3) and a negative exponent of 1/3...I am really thrown off by this.\r<BR>\n" );
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document.write( "Please explain<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618646 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let f(x) = x^(5/3) + 5x^(2/3)\r<BR>\n" );
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document.write( "f'(x) = (5/3)x^(2/3) + (10/3)x^(-1/3) = 0\r<BR>\n" );
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document.write( "someone told me you can factor out an x^(1/3) but how does that work when there is 5/3x and 10/3 there and ones an exponent of (2/3) and a negative exponent of 1/3...I am really thrown off by this.<BR>\n" );
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document.write( "f'(x) = (5/3)x^(2/3) + (10/3)x^(-1/3) = 0<BR>\n" );
document.write( "Since it's = 0, you can multiply by x^(1/3)<BR>\n" );
document.write( "--> (5/3)x + 10/3 = 0<BR>\n" );
document.write( "--> x = -2<BR>\n" );
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document.write( "You didn't give a reason for f' being = 0, tho.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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