document.write( "Question 1001468: If \"f%28x%29+=+%28x%5E2+-+a%5E2%29%2F%28x+-+a%29\" , when I find the value when \"x=a\", its \"0%2F0\" which is, well you know.\r
\n" ); document.write( "\n" ); document.write( "But when I further simplify the function, I get \"f%28x%29+=+x+%2B+a\" , which has a value for \"x+=+a\", which is \"2a\".\r
\n" ); document.write( "\n" ); document.write( "Is it a problem in maths or what?
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Algebra.Com's Answer #618636 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
no - there's no problem at all.\r
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\n" ); document.write( "\n" ); document.write( "the simplified equation is a new and separate equation from the original equation it was derived from.\r
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\n" ); document.write( "\n" ); document.write( "the domain of the simplified equation is different from the domain of the original equation.\r
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\n" ); document.write( "\n" ); document.write( "there are rules for analyzing rational functions.\r
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\n" ); document.write( "\n" ); document.write( "the simplified equation is useful to tell you whrere the asymptotes are.\r
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\n" ); document.write( "\n" ); document.write( "but you can't expect the simplified equation to have the same undefined points as the original equation because it's a different equation that stands on its own.\r
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\n" ); document.write( "\n" ); document.write( "an example:\r
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\n" ); document.write( "\n" ); document.write( "find the vertical asymptotes for y = ((x-1)*(x+1))/((x-1)*(x+5))\r
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\n" ); document.write( "\n" ); document.write( "y is undefined at x = 1 and x = -5, but there is a vertical asymptote only at x = -5.\r
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\n" ); document.write( "\n" ); document.write( "here's the graph:\r
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\n" ); document.write( "\n" ); document.write( "you can see from the graph that there is a vertical asymptote at x = -5.\r
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\n" ); document.write( "\n" ); document.write( "what you can't see is that the value of the function is undefined at x = 1, but there is a hole there, even if there is no asymptote.\r
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\n" ); document.write( "\n" ); document.write( "what has happened is that the (x-1) cancels out and you get the simplified equation that only has (x+5) in the denominator.\r
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\n" ); document.write( "\n" ); document.write( "if the factor in the denominator cancels out when you simplify the eqaution, there is no vertical asymptote at that point.\r
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\n" ); document.write( "\n" ); document.write( "if it doesn't cancel out, there is an asymptote at that point.\r
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\n" ); document.write( "\n" ); document.write( "the following table will, however, show you that the value of the original equation is undefined at x = 1 and at x = -5, while the value of the simplified equation is only undefined at x = -5.\r
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\n" ); document.write( "\n" ); document.write( "\"$$$\"\r
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\n" ); document.write( "\n" ); document.write( "the original equation and the simplified equation are two different equations with two different domains.\r
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\n" ); document.write( "\n" ); document.write( "the simplified equation is useful to tell you what the value of the hole is in the original equation.\r
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\n" ); document.write( "\n" ); document.write( "here's some references that might help you to understand better.\r
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\n" ); document.write( "\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut40_ratgraph.htm\r
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\n" ); document.write( "\n" ); document.write( "http://sites.csn.edu/istewart/mathweb/math126/graph_rational_func/graph_rational_func.htm\r
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