document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001336>Question 1001336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On the first part of a 317-mile trip, a salesman averaged 58 miles per hour. He averaged only 52 miles per hour on the last part of the trip because of an increased volume of traffic. Find the amount of time at EACH of the speeds if the total time was 5 hours and 45 minutes.  ---I'm confused on how to do this, if the 52 miles per hour happened because of traffic, are we supposed to assume 58 miles per hour again? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618568 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> On the first part of a 317-mile trip, a salesman averaged 58 miles per hour.<BR>\n" );
document.write( " He averaged only 52 miles per hour on the last part of the trip because of an increased volume of traffic.<BR>\n" );
document.write( " Find the amount of time at EACH of the speeds if the total time was 5 hours and 45 minutes.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Change 5 hr 45 min to 5.75 hrs<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let d = distance driven at 58 mph<BR>\n" );
document.write( "Total dist is 317, therefore<BR>\n" );
document.write( "(317-d) = distance driven at 52 mph<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Write a time equation; time = dist/speed<BR>\n" );
document.write( "time at 58mph + time at 52mph = 5.75 hrs<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F58 ALIGN=MIDDLE  ALT=\"d%2F58\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28317-d%29%29%2F52 ALIGN=MIDDLE  ALT=\"%28%28317-d%29%29%2F52\"   DISABLED_style= \"max-width:90%; height:auto;\" >  = 5.75<BR>\n" );
document.write( "multiply equation by least common multiple of 58 & 52, that is 1508<BR>\n" );
document.write( "1508*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F58 ALIGN=MIDDLE  ALT=\"d%2F58\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 1508*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28317-d%29%29%2F52 ALIGN=MIDDLE  ALT=\"%28%28317-d%29%29%2F52\"   DISABLED_style= \"max-width:90%; height:auto;\" >  = 1508*5.75<BR>\n" );
document.write( "cancel the denominators<BR>\n" );
document.write( "26d + 29(317-d) = 8671<BR>\n" );
document.write( "26d + 9193 - 29d = 8671<BR>\n" );
document.write( "26d - 29d = 8671 - 9193<BR>\n" );
document.write( "-3d = -522<BR>\n" );
document.write( "d = -522/-3<BR>\n" );
document.write( "d = +174 mi at 58 mph<BR>\n" );
document.write( "then<BR>\n" );
document.write( "317 - 174 = 143 mi at 52 mph<BR>\n" );
document.write( "\"Find the amount of time at EACH of the speeds\"<BR>\n" );
document.write( "174/58 = 3hrs at 58 mph<BR>\n" );
document.write( "and<BR>\n" );
document.write( "143/52 = 2.75 hrs at 52 mph<BR>\n" );
document.write( ";<BR>\n" );
document.write( ":<BR>\n" );
document.write( "We can check this by noting the two times do add up 5.75 which is 5 hrs 45 min </SPAN>\n" );
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