document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001297>Question 1001297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the cost was $20 in 1998 and $40 in 2008, then what is the average rate of change of the cost for that time period? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618541 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It doubles in 10 years<BR>\n" );
document.write( "p=Poe^rt<BR>\n" );
document.write( "p/Po=2<BR>\n" );
document.write( "2=e^rt<BR>\n" );
document.write( "ln of both sides, t=10<BR>\n" );
document.write( "0,0693=10r<BR>\n" );
document.write( "r=6.93%. It is an interest problem with continuous compounding, </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );