document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001267>Question 1001267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.\r<BR>\n" );
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document.write( "(6,-1) and 3y+x=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618500 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 3y+x=3, let's put it into slope-intercept form to find the slope...<BR>\n" );
document.write( "3y = -x + 3<BR>\n" );
document.write( "y (-1/3)x + 1<BR>\n" );
document.write( "So if we need a perpendicular line it is the negative reciprocal of (-1/3).<BR>\n" );
document.write( "That would be 3.<BR>\n" );
document.write( "Now plug that and the point (6,-1) into y = mx + b to find b:<BR>\n" );
document.write( "-1 = 3(6) + b<BR>\n" );
document.write( "-1 = 18 + b<BR>\n" );
document.write( "b = -19<BR>\n" );
document.write( "and<BR>\n" );
document.write( "y = 3x - 19 </SPAN>\n" );
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