document.write( "Question 1001164: 5 years ago a mother was 7 times as old as her daughter. 5 years hence she will be 3 times as old as her daughter. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #618496 by fractalier(6550)\"\" \"About 
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Call mom's age now, m.
\n" ); document.write( "Call the daughter's age now, d.
\n" ); document.write( "Then, five years ago,
\n" ); document.write( "m-5=7(d-5)=7d-35 or
\n" ); document.write( "m = 7d - 30
\n" ); document.write( "and five years hence,
\n" ); document.write( "m+5=3(d+5)=3d+15 or
\n" ); document.write( "m = 3d + 10
\n" ); document.write( "We can set them equal, since the m's are the same...so
\n" ); document.write( "7d - 30 = 3d + 10
\n" ); document.write( "4d = 40
\n" ); document.write( "d = 10
\n" ); document.write( "m = 40
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