document.write( "Question 1001164: 5 years ago a mother was 7 times as old as her daughter. 5 years hence she will be 3 times as old as her daughter. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #618496 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call mom's age now, m. \n" ); document.write( "Call the daughter's age now, d. \n" ); document.write( "Then, five years ago, \n" ); document.write( "m-5=7(d-5)=7d-35 or \n" ); document.write( "m = 7d - 30 \n" ); document.write( "and five years hence, \n" ); document.write( "m+5=3(d+5)=3d+15 or \n" ); document.write( "m = 3d + 10 \n" ); document.write( "We can set them equal, since the m's are the same...so \n" ); document.write( "7d - 30 = 3d + 10 \n" ); document.write( "4d = 40 \n" ); document.write( "d = 10 \n" ); document.write( "m = 40 \n" ); document.write( " |