document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001265>Question 1001265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a pile of coins, there are 15 more quarters than loonies($1) the total amount of quarters and loonies is $21.25 how many quarters are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618495 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of quarters and loonies, x and y.<BR>\n" );
document.write( "Then we know x = y + 15, or x - y = 15.<BR>\n" );
document.write( "The value equation is<BR>\n" );
document.write( ".25x+(1)y = 21.25<BR>\n" );
document.write( "We can add the first equation from the second and get<BR>\n" );
document.write( ".25x + y = 21.25<BR>\n" );
document.write( "x - y = 15<BR>\n" );
document.write( "and<BR>\n" );
document.write( "1.25x=36.25<BR>\n" );
document.write( "and <BR>\n" );
document.write( "x= 29 quarters  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );