document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001210>Question 1001210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Actinium-225 has a half-life of 10 days. Suppose we have an initial amount of 100 grams of actinium-225. How much would be present after 30 days </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618442 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Actinium-225 has a half-life of 10 days. Suppose we have an initial amount of 100 grams of actinium-225. How much would be present after 30 days <BR>\n" );
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document.write( "A(t) = Ao*(1/2)^(t/10)<BR>\n" );
document.write( "A(10) = 100*(1/2)^(30/10)<BR>\n" );
document.write( "A(10) = 100*(1/2)^3 = 12.5 grams<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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