document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001198>Question 1001198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is now twice as old as his friend. Five years ago, a man was thrice as old as his friend. Determine their present ages\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618439 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call his age now, x.<BR>\n" );
document.write( "Cal his friend's age now, y.<BR>\n" );
document.write( "Then we have<BR>\n" );
document.write( "x = 2y <BR>\n" );
document.write( "and five years ago<BR>\n" );
document.write( "x-5=3(y-5)<BR>\n" );
document.write( "Substitute the first equation into the second and get<BR>\n" );
document.write( "2y-5=3(y-5)<BR>\n" );
document.write( "2y - 5 = 3y - 15<BR>\n" );
document.write( "and <BR>\n" );
document.write( "y = 10<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "x = 20 </SPAN>\n" );
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