document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001190>Question 1001190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 83. the largest number is eight times the smallest, and the smallest is three times less than the middle number. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618437 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the smallest number x. The largest number is:<BR>\n" );
document.write( "8x And the middle number is:<BR>\n" );
document.write( "x+3 (3 times less than middle is the same as the middle is smallest plus 3)<BR>\n" );
document.write( "-----------------------------<BR>\n" );
document.write( "So now we have that:<BR>\n" );
document.write( "x+8x+x+3= 83<BR>\n" );
document.write( "10x+3= 83 Subtract 3 on both sides:<BR>\n" );
document.write( "10x= 80 Divide both sides by 10:<BR>\n" );
document.write( "x= 8<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "8+8(8)+(8+3)= 83<BR>\n" );
document.write( "8+64+11= 83<BR>\n" );
document.write( "83= 83 We have the correct answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );