document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001065>Question 1001065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the measures of all three angles is 180 degrees. if 2 angles have measures of 3a and then third angle measures 2a-28 calculate a. then calculate the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618408 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hi there,<BR>\n" );
document.write( "2 angles have measures of 3a<BR>\n" );
document.write( "= 6a<BR>\n" );
document.write( "Third angle measures 2a - 28<BR>\n" );
document.write( "All three angles = 180 degrees.<BR>\n" );
document.write( "6a + 2a - 28 = 180<BR>\n" );
document.write( "8a = 180 + 28<BR>\n" );
document.write( "8a = 208<BR>\n" );
document.write( "a = 26 degrees.<BR>\n" );
document.write( "2 angles = 78 degrees apiece.(3a) = (3(26))<BR>\n" );
document.write( "3rd angle = 24 degrees (2a - 28)<BR>\n" );
document.write( "(52 - 28)<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );