document.write( "Question 1001080: Hello Friends,\r
\n" ); document.write( "\n" ); document.write( "Help! So lost on these Slope and Linear scenarios. \r
\n" ); document.write( "\n" ); document.write( "1. Given the linear equation y=-3/4x-3, find the y-coordinates of the points
\n" ); document.write( "(-8, ), (-4, ), and (4, ).Plot those points and graph the linear equation. \r
\n" ); document.write( "\n" ); document.write( "2. Given the linear equation y=-1/3x+6, find the y-coordinates of the points
\n" ); document.write( "(-9, ), (-3, ), and (6, ). Plot those points and graph the linear equation.
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\n" ); document.write( "3. Write the slope-intercept equation for the line that passes through (14, -2) and is perpendicular to 7x – 10y = 18\r
\n" ); document.write( "\n" ); document.write( "4. Write the slope-intercept equation for the line that passes through (1, -9) and (3, -1). \r
\n" ); document.write( "\n" ); document.write( "Thanking you in advance\r
\n" ); document.write( "\n" ); document.write( "Betty
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Algebra.Com's Answer #618364 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
1. Given the linear equation \"y=-%283%2F4%29x-3\", find the y-coordinates of the points
\n" ); document.write( "(\"-8\", \"3\" ), =>\"y=-%283%2Fcross%284%291%29%28-cross%288%292%29-3\"=>\"y=-%283%29%28-2%29-3\"=>\"y=6-3\"=>\"y=3\"\r
\n" ); document.write( "\n" ); document.write( "(\"-4\",\"0\" ), =>\"y=-%283%2Fcross%284%291%29%28-cross%284%291%29-3\"=>\"y=-%283%29%28-1%29-3\"=>\"y=3-3\"=>\"y=0\"
\n" ); document.write( "(\"4\",\"-6\" )=>\"y=-%283%2Fcross%284%291%29%28cross%284%291%29-3\"=>\"y=-%283%29%281%29-3\"=>\"y=-3-3\"=>\"y=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Plot those points and graph the linear equation.\r
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\n" ); document.write( "\n" ); document.write( "2. Given the linear equation \"y=-%281%2F3%29x%2B6\", find the y-coordinates of the points\r
\n" ); document.write( "\n" ); document.write( "(\"-9\",\"9\" ), =>\"y=-%281%2Fcross%283%291%29%28-cross%289%293%29%2B6\"=>\"y=-%281%29%28-3%29%2B6\"=>\"y=3%2B6\"=>\"y=9\"
\n" ); document.write( "(\"-3\",\"7\" ),=>\"y=-%281%2Fcross%283%291%29%28-cross%283%291%29%2B6\"=>\"y=-%281%29%28-1%29%2B6\"=>\"y=1%2B6\"=>\"y=7\"
\n" ); document.write( "(\"6\",\"4\" )=>\"y=-%281%2Fcross%283%291%29%28cross%286%292%29%2B6\"=>\"y=-%281%29%282%29%2B6\"=>\"y=-2%2B6\"=>\"y=4\" \r
\n" ); document.write( "\n" ); document.write( "Plot those points and graph the linear equation.
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\n" ); document.write( "\n" ); document.write( "3. Write the slope-intercept equation for the line that passes through (\"14\",\"+-2\") and is perpendicular to \"7x+-10y+=+18\"\r
\n" ); document.write( "\n" ); document.write( "the slope-intercept form of the given equation\r
\n" ); document.write( "\n" ); document.write( "\"7x+-18+=+10y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=+%287%2F10%29x+-9%2F5+\"\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"7%2F10\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%287%2F10%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%2810%2F7%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=-10%2F7\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"-10%2F7\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"-10%2F7\" (its the negative reciprocal of \"7%2F10\" from the line \"y=%287%2F10%29%2Ax-9%2F5\").\n" ); document.write( "Also since the unknown line goes through (14,-2), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y%2B2=%28-10%2F7%29%2A%28x-14%29\" Plug in \"m=-10%2F7\", \"x%5B1%5D=14\", and \"y%5B1%5D=-2\"
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\n" ); document.write( " \"y%2B2=%28-10%2F7%29%2Ax%2B%2810%2F7%29%2814%29\" Distribute \"-10%2F7\"
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\n" ); document.write( " \"y%2B2=%28-10%2F7%29%2Ax%2B140%2F7\" Multiply
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\n" ); document.write( " \"y=%28-10%2F7%29%2Ax%2B140%2F7-2\"Subtract \"-2\" from both sides to isolate y
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\n" ); document.write( " \"y=%28-10%2F7%29%2Ax%2B140%2F7-14%2F7\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%28-10%2F7%29%2Ax%2B126%2F7\" Combine the fractions
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\n" ); document.write( " \"y=%28-10%2F7%29%2Ax%2B18\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%287%2F10%29%2Ax-9%2F5\" and goes through (\"14\",\"-2\") is \"y=%28-10%2F7%29%2Ax%2B18\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%287%2F10%29%2Ax-9%2F5\" and \"y=%28-10%2F7%29%2Ax%2B18\"
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\n" ); document.write( " graph of the given equation \"y=%287%2F10%29%2Ax-9%2F5\" (red) and graph of the line \"y=%28-10%2F7%29%2Ax%2B18\"(green) that is perpendicular to the given graph and goes through (\"14\",\"-2\")
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\n" ); document.write( "\n" ); document.write( "4. Write the slope-intercept equation for the line that passes through (\"1\", \"-9\") and (\"3\", \"-1\"). \r
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Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (1, -9) and (x2, y2) = (3, -1).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-1--9%29%2F%283-1%29+=+4\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"4%2A1+%2Bb+=+-13\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=-9-4%2A1+=+-13\".
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\n" ); document.write( " y=(4)x + (-13)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"y=4x+-13\"\r
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