document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001101>Question 1001101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a student added 14 to a number, the result is 1/3 of the number.  What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618354 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When a student added 14 to a number, the result is 1/3 of the number. What is the number? <BR>\n" );
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document.write( "Let the number be \"x\"::<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x + 14 = (1/3)x<BR>\n" );
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document.write( "Subtract (1/3)x from both sides of the equation::<BR>\n" );
document.write( "Subtract 14 from both sides of the equation::<BR>\n" );
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document.write( "(2/3)x = -14<BR>\n" );
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document.write( "Divide both sides of the equation by (2/3) to get:<BR>\n" );
document.write( "x = (-14)/(2/3) = -7*3 = -21<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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