document.write( "Question 1001031: A farmer has chickens and goats,with at least one of each. The chickens and goats together have a total of 100 legs. (4 legs per goat and 2 legs per chicken) How many different combinations of chickens and goats could there be? Sorry for not knowing the right category. But all I have so far is 4x+2y=100 \n" ); document.write( "
Algebra.Com's Answer #618329 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! A farmer has chickens and goats,with at least one of each. \n" ); document.write( "The chickens and goats together have a total of 100 legs. \n" ); document.write( "(4 legs per goat and 2 legs per chicken) How many different \n" ); document.write( "combinations of chickens and goats could there be? Sorry \n" ); document.write( "for not knowing the right category. But all I have so far \n" ); document.write( "is 4x+2y=100 \n" ); document.write( " \r\n" ); document.write( "You are letting x be the number of goats and y be the number \r\n" ); document.write( "of chickens. Divide that through by 2\r\n" ); document.write( "\r\n" ); document.write( " 2x+y=50\r\n" ); document.write( " y=50-2x\r\n" ); document.write( "\r\n" ); document.write( "If they were all goats and no chickens,\r\n" ); document.write( "thre would be x = 100/4 = 25 goats. But we must\r\n" ); document.write( "have at least 1 chicken, so the number of\r\n" ); document.write( "goats, x, can only be 1 to 24, inclusive. So \r\n" ); document.write( "there are 24 combinations of goats and chickens.\r\n" ); document.write( "\r\n" ); document.write( " 1. x=1 goat and y=50-2(1) = 50-2 = 48 chickens.\r\n" ); document.write( " 2. x=2 goats and y=50-2(2) = 50-4 = 46 chickens.\r\n" ); document.write( " 3. x=3 goats and y=50-2(3) = 50-6 = 44 chickens.\r\n" ); document.write( " 4. x=4 goats and y=50-2(4) = 50-8 = 42 chickens.\r\n" ); document.write( " 5. x=5 goats and y=50-2(5) = 50-10 = 40 chickens.\r\n" ); document.write( " 6. x=6 goats and y=50-2(6) = 50-12 = 38 chickens.\r\n" ); document.write( " 7. x=7 goats and y=50-2(7) = 50-14 = 36 chickens.\r\n" ); document.write( " 8. x=8 goats and y=50-2(8) = 50-16 = 34 chickens.\r\n" ); document.write( " 9. x=9 goats and y=50-2(9) = 50-18 = 32 chickens.\r\n" ); document.write( "10. x=10 goats and y=50-2(10) = 50-20 = 30 chickens.\r\n" ); document.write( "11. x=11 goats and y=50-2(11) = 50-22 = 28 chickens.\r\n" ); document.write( "12. x=12 goats and y=50-2(12) = 50-24 = 26 chickens.\r\n" ); document.write( "13. x=13 goats and y=50-2(13) = 50-26 = 24 chickens.\r\n" ); document.write( "14. x=14 goats and y=50-2(14) = 50-28 = 22 chickens.\r\n" ); document.write( "15. x=15 goats and y=50-2(15) = 50-30 = 20 chickens.\r\n" ); document.write( "16. x=16 goats and y=50-2(16) = 50-32 = 18 chickens.\r\n" ); document.write( "17. x=17 goats and y=50-2(17) = 50-34 = 16 chickens.\r\n" ); document.write( "18. x=18 goats and y=50-2(18) = 50-36 = 14 chickens.\r\n" ); document.write( "19. x=19 goats and y=50-2(19) = 50-38 = 12 chickens.\r\n" ); document.write( "20. x=20 goats and y=50-2(20) = 50-40 = 10 chickens.\r\n" ); document.write( "21. x=21 goats and y=50-2(21) = 50-42 = 8 chickens.\r\n" ); document.write( "22. x=22 goats and y=50-2(22) = 50-44 = 6 chickens.\r\n" ); document.write( "23. x=23 goats and y=50-2(23) = 50-46 = 4 chickens.\r\n" ); document.write( "24. x=24 goats and y=50-2(24) = 50-48 = 2 chickens.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |