document.write( "Question 1000927: A farmer can plow a field in 4 days by using a tractor. A hired hand can plow the same field in 6 days by using a smaller tractor. How many days will be required for the plowing if they work together? \n" ); document.write( "

Algebra.Com's Answer #618269 by josgarithmetic(39617) $\"\"$ $\"About$

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$\"1%2F%281%2F4%2B1%2F6%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "The combined rate of both machines working together is the sum of their individual rates. The unit of rate will be in FIELD per DAY.\r
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document.write( "Machine          RATE in Fields per Day\r\n" );
document.write( "Tractor           1/4\r\n" );
document.write( "Smaller Tractor   1/6\r\n" );
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\n" ); document.write( "\n" ); document.write( "The rate for both working together is $\"1%2F4%2B1%2F6\"$ but you want the number as DAYS per FIELD, and this would be the reciprocal of $\"1%2F4%2B1%2F6\"$ , so that means $\"1%2F%281%2F4%2B1%2F6%29\"$ DAYS for 1 field.\r
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\n" ); document.write( "\n" ); document.write( "This question is not about finding any equation, but only handling a rate. Maybe you wanted something like D is how many days, and 1 field would be done according to rate $\"1%2FD\"$ , and then $\"1%2F4%2B1%2F6=1%2FD\"$ ? \n" ); document.write( "

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