document.write( "Question 1000937: One pair of integer values satisfy the equation x^2+y^2=100 is x=6 and y=8. Find pair of integer values that satisfy x^2+6x+y^2-4y-87=0. Thanks in advance! \n" ); document.write( "
Algebra.Com's Answer #618263 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "With equation of a circle: \n" ); document.write( "x^2 + y^2 + 6x - 4y - 87 = 0 \n" ); document.write( "The centre of the circle is (-3,2) \n" ); document.write( "The radius = 10 \n" ); document.write( "(sqrt (-3)^2 + (2)^2 -(-87)) \n" ); document.write( "If you move along horizontally from \n" ); document.write( "coordinates (-3,2) by 10 units the \n" ); document.write( "set of coordinates (7,2) is reached. \n" ); document.write( "This point is on the circle. \n" ); document.write( "These will satisfy the equation:- \n" ); document.write( "x^2 + y^2 + 6x - 4y - 87 =0 \n" ); document.write( "(7)^2 +(2)^2 + 6(7) - 4(2) - 87 = 0 \n" ); document.write( "49 + 4 + 42 - 8 - 87 = 0 \n" ); document.write( "Hope this helps :-)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |