document.write( "Question 1000937: One pair of integer values satisfy the equation x^2+y^2=100 is x=6 and y=8. Find pair of integer values that satisfy x^2+6x+y^2-4y-87=0. Thanks in advance! \n" ); document.write( "
Algebra.Com's Answer #618263 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "With equation of a circle:
\n" ); document.write( "x^2 + y^2 + 6x - 4y - 87 = 0
\n" ); document.write( "The centre of the circle is (-3,2)
\n" ); document.write( "The radius = 10
\n" ); document.write( "(sqrt (-3)^2 + (2)^2 -(-87))
\n" ); document.write( "If you move along horizontally from
\n" ); document.write( "coordinates (-3,2) by 10 units the
\n" ); document.write( "set of coordinates (7,2) is reached.
\n" ); document.write( "This point is on the circle.
\n" ); document.write( "These will satisfy the equation:-
\n" ); document.write( "x^2 + y^2 + 6x - 4y - 87 =0
\n" ); document.write( "(7)^2 +(2)^2 + 6(7) - 4(2) - 87 = 0
\n" ); document.write( "49 + 4 + 42 - 8 - 87 = 0
\n" ); document.write( "Hope this helps :-)\r
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