document.write( "Question 1000939: How many different ways can a club choose a committee of 4 from 15 members? \n" ); document.write( "
Algebra.Com's Answer #618254 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! How many different ways can a club choose a committee of 4 from 15 members? \n" ); document.write( "----------- \n" ); document.write( "The 1st choice is 1 of 15. \n" ); document.write( "Then 14, 13 & 12 \n" ); document.write( "--> 15*14*13*12 = 32760 ways \n" ); document.write( "=============== \n" ); document.write( "If there is no difference between the members, then A,B,C&D is the same as C,B,A,&D, etc. \n" ); document.write( "--> 4*3*2*1 = 24 different ways the can be chosen. \n" ); document.write( "32760/24 = 1365 different ways. \n" ); document.write( " \n" ); document.write( " |