document.write( "Question 1000900: 1(a) Given the universal set U={1,2,3,…,9} and the sets
\n" ); document.write( " A={1,2,3,4,5}; B={4,5,6,7}; C={1,3,5,7,9}; D={2,4,6,8}.
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\n" ); document.write( "Consider the relation R= {(1,a); (2,d); (3,a); (3,b); (3,d)} and S= {(b,x); (b,z), (c,y); (d,z)}.Find S-1 o R-1
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Algebra.Com's Answer #618216 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
1(a) Given the universal set U={1,2,3,…,9} and the sets
\n" ); document.write( " A={1,2,3,4,5}; B={4,5,6,7}; C={1,3,5,7,9}; D={2,4,6,8}.
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document.write( "That's the set of all elements of B that are not elements of B\r\n" );
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document.write( "From B = {4,5,6,7}, we take out any of these A={1,2,3,4,5} which\r\n" );
document.write( "B contains.  A contains 4 and 5, which A also contains, so we \r\n" );
document.write( "remove 4 and 5 from B and we have {6,7}.\r\n" );
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document.write( "Therefore B-A = {6,7}\r\n" );
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document.write( "(ii)(A-D)c\r\n" );
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document.write( "We first find what's in the parentheses, A-D\r\n" );
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document.write( "From A={1,2,3,4,5}, we take out any of these D={2,4,6,8} which\r\n" );
document.write( "A contains.  D contains 2 and 4, which A also contains, so we \r\n" );
document.write( "remove 2 and 4 from A and we have {1,3,5}.\r\n" );
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document.write( "So A-D = {1,3,5}\r\n" );
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document.write( "So to find the complement of that set, (A-D)c,\r\n" );
document.write( "we form the set of all elements in the universal set U={1,2,3,…,9}\r\n" );
document.write( "which are not elements of A-D, which is {1,3,5}. So we remove\r\n" );
document.write( "1,3 and 5 from the universal set U={1,2,3,…,9} and we have\r\n" );
document.write( "{2,4,6,7,8,9}\r\n" );
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document.write( "So (A-D)c = {2,4,6,7,8,9}\r\n" );
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document.write( "We are only supposed to answer 2 questions per post.\r\n" );
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document.write( "Edwin
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