document.write( "Question 1000904:  Peter can cycle twice as fast as Amy. Find
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document.write( "i Amy’s cycling speed to Peter’s speed
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document.write( "ii Peter’s cycling speed to Amy’s speed\r
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document.write( "B 
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document.write( "Do we know the cycling speed of each person?\r
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| Algebra.Com's Answer #618215 by Theo(13342)     You can put this solution on YOUR website! x = amy's cycling speed. \n" ); document.write( "y = peter's cycling speed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "peter cycles twice as fast as amy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 1/2 * y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "amy cycles half as far as peter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we do not know the cycling speed of either peter or amy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we only know that peters cycles twice as fast as amy and that amy cycles half as fast as peter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if we knew peters's cycling speed, we could find amy's.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if we knew amy's cycling speed, we could find peter's.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we only know that, whatever amy's speed is, peter's is twice as fast.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we only know that, whatever peter's speed is, amy's is half as fast.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |