document.write( "Question 1000871: How do you graph a slope of -2/1 and a y intercept of -6,3? \n" ); document.write( "
Algebra.Com's Answer #618199 by Theo(13342) You can put this solution on YOUR website! you cannot have a y-intercept of (-6,3).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the y-intercept is the value of y when x = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the x-coordinate of the point that contains the y-intercept must be equal to 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "what you were given was a point and a slope as far as i can tell.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that point will be on the line but it is not the y-intercept.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the slope is -2/1 and the point is (-6,3).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you plot the point (-6,3) on your graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you pick any other value of x that's reasonably far enough away to that it's easy for you to draw a straight line between that new point and the original point.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'll pick x = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this will allow me to find the new point and the y-intercept at the same time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the change in x is from -6 to 0 which is a change of 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the change in y, i multiply that change by -2/1. \n" ); document.write( "this result in a change in y of -2*6 = -12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the change in the value of x is 6. \n" ); document.write( "the change in the value of y is -12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from the point (-6,3), add 6 to the x-coordinate and subtract 12 from the y-coordinate to get (0,-9).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the point (0,-9) is the y-intercept. \n" ); document.write( "it's the value of y when the value of x is 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "draw a straight line between the points (-6,3) and (0,-9). \n" ); document.write( "that's your graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the slope intercept form of the equation of a straight line is y = mx + b. \n" ); document.write( "m is the slope and b is the y-intercept.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation is y = -2/1 * x - 9. \n" ); document.write( "-2/1 is the slope. \n" ); document.write( "-9 is the y-intercept.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of y = -2/1 * x - 9 is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a good reference you can use to learn more about linear equations. \n" ); document.write( "http://www.mathsisfun.com/algebra/linear-equations.html\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |