document.write( "Question 1000680: a positive integer is 5 less than another if the reciprocal of the smaller integer is subtracted from 3 times the reciprocals of the larger than the result is 1/12 \n" ); document.write( "
Algebra.Com's Answer #618156 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a positive integer is 5 less than another \n" ); document.write( "a = b - 5 \n" ); document.write( " if the reciprocal of the smaller integer is subtracted from 3 times the reciprocals of the larger than the result is 1/12 \n" ); document.write( " \n" ); document.write( "Replace a with (b-5) from the 1st statement \n" ); document.write( " \n" ); document.write( "Multiply equation by 12b(b-5), cancel the denominators \n" ); document.write( "12(3)(b-5) - 12b = b(b-5) \n" ); document.write( "36a - 180 - 12b = b^2 - 5b \n" ); document.write( "24a - 180 = b^2 - 5b \n" ); document.write( "Form a quadratic equation on the right \n" ); document.write( "0 = b^2 - 5b - 24a + 180 \n" ); document.write( "b^2 - 29b + 180 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(b-20)(b-9) = 0 \n" ); document.write( "two solutions \n" ); document.write( "b = 20, then a = 15 \n" ); document.write( "b = 9, then a = 4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check the first pair in the original equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You can check the 2nd pair in the same equation \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |