document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000774>Question 1000774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation and please explain step by step<BR>\n" );
document.write( "log(3+x)-log(x-4)=log2\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618107 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The difference of logs is the log of a quotient, so that from<BR>\n" );
document.write( "log(3+x)-log(x-4)=log2  we get<BR>\n" );
document.write( "log[(3+x)/(x-4)]=log 2<BR>\n" );
document.write( "Now exponentiate ten-to-the and get<BR>\n" );
document.write( "(3+x)(x-4)= 2<BR>\n" );
document.write( "x^2-x-12=2<BR>\n" );
document.write( "x^2-x-14=0<BR>\n" );
document.write( "Now apply the quadratic formula, since this doesn't factor...<BR>\n" );
document.write( "x = [1 +- sqrt(57)]/2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );