document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000716>Question 1000716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8^(x+3)=9^x<BR>\n" );
document.write( "x=52.965 but please explain how to get there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618052 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 8^(x+3)=9^x, apply laws of logs to get<BR>\n" );
document.write( "log(8^(x+3))=log(9^x)<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(x+3)log8 = xlog9<BR>\n" );
document.write( "xlog8 + 3 log 8 = x log 9<BR>\n" );
document.write( "Collect like terms and solve for x...<BR>\n" );
document.write( "xlog8-xlog9 = - 3log8<BR>\n" );
document.write( "x(log8-log9)=-3log8<BR>\n" );
document.write( "x = -3log8 / (log8-log9)<BR>\n" );
document.write( "Now plug in values<BR>\n" );
document.write( "x = -3(.903)/(.903-.954)<BR>\n" );
document.write( "x = 52.965 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );