document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000657>Question 1000657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a certain number is increased by 5,half of the result is three fifth of the excess of 61 over that number.Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618050 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I understand what you wrote, we can call the unknown, x, and write<BR>\n" );
document.write( "(1/2)(x + 5) = (3/5)(61-x)<BR>\n" );
document.write( "Multiply everything by ten and get<BR>\n" );
document.write( "5(x+5)=6(61-x)<BR>\n" );
document.write( "5x+25 = 366 - 6x<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "11x = 341<BR>\n" );
document.write( "Divide by 11 and<BR>\n" );
document.write( "x = 31 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );