document.write( "Question 12177: Juan has 15 pennies and 8 more nickles than dimes. He has 51 coins in all. How many dimes does he have? \n" ); document.write( "

Algebra.Com's Answer #6180 by bonster(299) $\"\"$ $\"About$

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Juan has 15 pennies
\n" ); document.write( "subtract 15 coins from 51
\n" ); document.write( "51-15=36 remaining coins\r
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\n" ); document.write( "\n" ); document.write( "8 more nickles than dimes
\n" ); document.write( "dimes=x
\n" ); document.write( "nickles=x+8\r
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\n" ); document.write( "\n" ); document.write( "the sum of the number of dimes and the number of nickles= 36
\n" ); document.write( "x+(x+8)=36
\n" ); document.write( "2x+8=36 <--subtract 8 from both sides
\n" ); document.write( "(2x+8)-8=36-8
\n" ); document.write( "2x=28 <--divide both sides by 2
\n" ); document.write( " $\"2x%2F2\"$ = $\"28%2F2\"$
\n" ); document.write( "x=14\r
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\n" ); document.write( "\n" ); document.write( "if dimes=x and x=14, he has 14 dimes
\n" ); document.write( "nickles=x+8=14+8=22 nickles\r
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\n" ); document.write( "\n" ); document.write( "he has 14 dimes\r
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\n" ); document.write( "\n" ); document.write( "Check: 14+22+15=51
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