document.write( "Question 1000550: 20 men can reap a field in 20 day.when should 5 men leave the work,if the whole field is to be reapedgin 24 day after they leave the work. \n" ); document.write( "
Algebra.Com's Answer #617959 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 20 men can reap a field in 20 days. \n" ); document.write( "Find how many man-days to do the job. \n" ); document.write( "20 * 20 = 400 man-days \n" ); document.write( ": \n" ); document.write( "when should 5 men leave the work, if the whole field is to be reaped in 24 days after they leave the work. \n" ); document.write( "let d = no. of days until the remaining 15 men finish in 24 days \n" ); document.write( "5d + 15(d+24) = 400 \n" ); document.write( "5d + 15d + 360 = 400 \n" ); document.write( "20d = 400 - 360 \n" ); document.write( "20d = 400 - 360 \n" ); document.write( "20d = 40 \n" ); document.write( "d = 40/20 \n" ); document.write( "d = 2 days \n" ); document.write( ": \n" ); document.write( "The 5 men can leave in 2 days \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( "5 * 2 = 10 man-days \n" ); document.write( "15(2 + 24) = 390 man-days \n" ); document.write( "--------------------- \n" ); document.write( "total: 400 man-days \n" ); document.write( " |