document.write( "Question 1000527: Use the bisection to find the positive root of the equation to the nearest tenth.\r
\n" ); document.write( "\n" ); document.write( "x^2-11=0 (Show procedures) \n" ); document.write( "
Algebra.Com's Answer #617924 by stanbon(75887)\"\" \"About 
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Use the bisection to find the positive root of the equation to the nearest tenth.
\n" ); document.write( "x^2-11=0 (Show procedures)
\n" ); document.write( "----
\n" ); document.write( "Factor::
\n" ); document.write( "(x-sqrt(11))(x+sqrt(11)) = 0
\n" ); document.write( "----
\n" ); document.write( "x = sqrt(11) or x = -sqrt(11)
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\n" ); document.write( "3^2 < 11 < 4^2
\n" ); document.write( "------
\n" ); document.write( "a------b-----(a+b)/2---[(a+b)/2]^2
\n" ); document.write( "3------4------3.5-------3.5^2 = 12.25---- > 11
\n" ); document.write( "3-----3.5-----3.25------3.25^2 = 10.56---- < 11
\n" ); document.write( "3.25--3.5-----3.375-----3.375^2 = 11.39---- > 11
\n" ); document.write( "etc
\n" ); document.write( "----
\n" ); document.write( "sqrt(11) = 3.32
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\n" ); document.write( "-sqrt(11) = -3.32
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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