document.write( "Question 1000413: x varies jointly with y and the cube of z and inversely with w. The value of x is 64 when y = 2, z = 4 and w = 6. Find x when y = 1, w = 15 and z = 3.
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Algebra.Com's Answer #617907 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "x varies jointly with y and the cube of z and inversely with w \n" ); document.write( "X = kYZ^3/W \n" ); document.write( "k = constant of proportionality \n" ); document.write( "Find 'k' \n" ); document.write( "X = kYZ^3/W \n" ); document.write( "64 = k24^3/6 \n" ); document.write( "k = (64 x 6)/(2 x 64) \n" ); document.write( "k = 3 \n" ); document.write( "Formula: \n" ); document.write( "X = 3YZ^3/W \n" ); document.write( "........... \n" ); document.write( "X = (3 x 1 x 3^3)/15 \n" ); document.write( "X = 5.4 \n" ); document.write( "Hope this helps. :-) \n" ); document.write( " |