document.write( "Question 1000271: 6^(3-4x) x 4^(x+4) = 2
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Algebra.Com's Answer #617819 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"6%5E%283-4x%29+%2A+4%5E%28x%2B4%29+=+2\"....use log\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%5E%283-4x%29+%2A+4%5E%28x%2B4%29%29+=log%28+2%29\"....write \"6%5E%283-4x%29\"as \"3%5E%283-4x%29%2A2%5E%283-4x%29\" and \"4%5E%28x%2B4%29%29\" as \"2%5E%282x%2B8%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%283%5E%283-4x%29%2A2%5E%283-4x%29+%2A2%5E%282x%2B8%29%29%29+=log%28%28+2%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"log%28%283%5E%283-4x%29%2A2%5E%283-4x%2B2x%2B8%29%29%29+=log%28%28+2%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"log%28%283%5E%283-4x%29%2A2%5E%2811-2x%29%29%29+=log%28%28+2%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"log%28%283%5E%283-4x%29%29%2Blog%28%282%5E%2811-2x%29%29%29%29+=log%28%28+2%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"%283-4x%29log%28%283%29%29%2B%2811-2x%29log%28%282%29%29%29+=log%28%28+2%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"3log%28%283%29%29%2B10log%28%282%29%29=2x%28log%28%283%29%29%2Blog%28%282%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%283log%28%283%29%29%2B10log%28%282%29%29%29%2F2%28log%28%283%29%29%2Blog%28%282%29%29%29\"\r
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