document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000333>Question 1000333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a particular rate of simple interest, $1200 invested at time t=0 will accumulate to $1300 in T years. find the accumulated value of $500 invested at the same rate of simple interest and again at t=0, but this time 2T years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617789 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i = p * r * n<BR>\n" );
document.write( "f = p + i\r<BR>\n" );
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document.write( "i = interest<BR>\n" );
document.write( "p = present value of investment.<BR>\n" );
document.write( "r = interest rate per time period<BR>\n" );
document.write( "n = number of time periods<BR>\n" );
document.write( "f = future value of investment\r<BR>\n" );
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document.write( "you are given that you invested 1200 and you had 1300 after T years.<BR>\n" );
document.write( "your interest is therefore equal to 100 because 1300 - 1200 = 100<BR>\n" );
document.write( "your interest rate is 100 / 1200 = 1/12 per time period<BR>\n" );
document.write( "your time period is T years.<BR>\n" );
document.write( "n is the number of time periods = 1.\r<BR>\n" );
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document.write( "applying the fomula to what you were given results in:\r<BR>\n" );
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document.write( "i = p * r * n, which becomes:\r<BR>\n" );
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document.write( "100 = 1200 * 1/12 * 1\r<BR>\n" );
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document.write( "since this gets you 100 = 100, the values given for the variables involved are good.\r<BR>\n" );
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document.write( "in the second part of your problem, you are given that  your initial investment is 500 and that it is invested at the same rate as in the first part of your problem, but for 2T years.\r<BR>\n" );
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document.write( "p = 500<BR>\n" );
document.write( "r = 1/12 per time period.<BR>\n" );
document.write( "n = 2 time periods.\r<BR>\n" );
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document.write( "you solve for i to get:\r<BR>\n" );
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document.write( "i = 500 * 1/12 * 2 = 500 * 2/12 = 83.33\r<BR>\n" );
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document.write( "f = p + i becomes f = 500 + 83.33 = 583.33\r<BR>\n" );
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document.write( " </SPAN>\n" );
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