document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000333>Question 1000333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a particular rate of simple interest, $1200 invested at time t=0 will accumulate to $1300 in T years. find the accumulated value of $500 invested at the same rate of simple interest and again at t=0, but this time 2T years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617785 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617785\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With simple interest<BR>\n" );
document.write( "I=prt<BR>\n" );
document.write( "100=1200*r*t<BR>\n" );
document.write( "rt=(1/12)<BR>\n" );
document.write( "r*2t=(1/6), which is the \"new\" rt for the second part<BR>\n" );
document.write( "I=prt; I=500*(1/6)=$83.33<BR>\n" );
document.write( "Accumulated value=$583.33 </SPAN>\n" );
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