document.write( "Question 1000268: Phyllis invested 55000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 6 percent per year. After one year the total interest earned on these investments was 3090 dollars. How much money did she invest at each rate?
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Algebra.Com's Answer #617775 by CountrySLP(2)\"\" \"About 
You can put this solution on YOUR website!
\"X+%2B+Y+=++55000\"
\n" ); document.write( "\"X+=+55000+-+Y\"
\n" ); document.write( "\"Y+=+55000+-+X\"\r
\n" ); document.write( "\n" ); document.write( "\"X+%2A0.05+%2B+Y%2A0.06+=+3090\"
\n" ); document.write( "--Substitute Y in terms of X
\n" ); document.write( "\"X%2A0.05+%2B+%2855000-X%29%2A0.06+=+3090\"
\n" ); document.write( "--Expand the 2nd expression
\n" ); document.write( "\"+%28X%2A0.05%29+%2B+%28%2855000%2A0.06%29-%28X%2A0.06%29%29+=+3090\"
\n" ); document.write( "\"+%28X%2A0.05%29+%2B+3300+-+%28X%2A0.06%29+=+3090\"
\n" ); document.write( "\"+%28X%2A0.05%29+-+%28X%2A0.06%29+=+3090+-+3300\"
\n" ); document.write( "\"+%28X%2A0.05%29-%28X%2A0.06%29+=+-210\"
\n" ); document.write( "--Compress the expression pulling out X
\n" ); document.write( "\"X%280.05-0.06%29+=+-210\"
\n" ); document.write( "\"X%28-0.01%29+=+-210+\"
\n" ); document.write( "\"X+=+-210%2F-0.01\"
\n" ); document.write( "\"X=21000\"
\n" ); document.write( "--Compute Y from X
\n" ); document.write( "\"Y+=+55000+-+X\"
\n" ); document.write( "\"Y+=+55000+-+21000\"
\n" ); document.write( "\"Y+=+34000\"\r
\n" ); document.write( "\n" ); document.write( "--Verify the answer
\n" ); document.write( "\"X+%2A0.05+%2B+Y%2A0.06+=+3090\"
\n" ); document.write( "\"+%2821000%2A0.05%29+%2B+%2834000%2A0.06%29+=+3090\"
\n" ); document.write( "\"1050+%2B+2040+=+3090\" **Correct!
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