document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=767524>Question 767524</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle and a square share a side. The hypotenuse of the triangle measures 10 cm. One base of the triangle measures 4 cm. Neither the known base nor the hypotenuse is the side that is shared with the square. Find the area of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617770 by </B><A HREF=/tutors/aboutme.mpl?userid=CountrySLP><B>CountrySLP(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CountrySLP><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Actually the answer would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=84 ALIGN=MIDDLE  ALT=\"84\"   DISABLED_style= \"max-width:90%; height:auto;\" > (not <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=84%5E2 ALIGN=MIDDLE  ALT=\"84%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >)  See below: \r<BR>\n" );
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document.write( "The length of the third triangle side would be solved as follows:<BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, ie.<BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%5E2+%2B+b%5E2+=+10%5E2 ALIGN=MIDDLE  ALT=\"4%5E2+%2B+b%5E2+=+10%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16+%2B+b%5E2+=+100 ALIGN=MIDDLE  ALT=\"16+%2B+b%5E2+=+100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+100+-+16 ALIGN=MIDDLE  ALT=\"b%5E2+=+100+-+16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+sqrt%2884%29 ALIGN=MIDDLE  ALT=\"b+=+sqrt%2884%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > which will be slightly larger than 9\r<BR>\n" );
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document.write( "This makes sense, because 10, as the hypotenuse, would be the longest side.\r<BR>\n" );
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document.write( "Therefore, one side of the square would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2884%29 ALIGN=MIDDLE  ALT=\"sqrt%2884%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Now, the area of the square would be computed as follows:<BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=+s%5E2 ALIGN=MIDDLE  ALT=\"a+=+s%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=+%28sqrt%2884%29%29+%2A+%28sqrt%2884%29%29 ALIGN=MIDDLE  ALT=\"a+=+%28sqrt%2884%29%29+%2A+%28sqrt%2884%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "	<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=+84 ALIGN=MIDDLE  ALT=\"a+=+84\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( " </SPAN>\n" );
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