document.write( "Question 1000251: Can u please solve this x for me log12(x+1)+log12^x=1 \n" ); document.write( "
Algebra.Com's Answer #617767 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Can u please solve this x for me log12(x+1)+log12^x=1
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If \"log+%2812%2C+%28x+%2B+1%29%29+%2B+log+%2812%2C+x%29+=+1\", then: 
\n" ); document.write( "\"highlight_green%28x+=+3%29\" OR x = - 4 (ignore) \n" ); document.write( "
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