document.write( "Question 1000305: Suppose that x=ln(A) and y=ln(B) . Write the following expressions in terms of x and y (so you cannot have A or B anywhere in your answers).\r
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\n" ); document.write( "\n" ); document.write( "Please help, I do not understand these. Thanks!
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Algebra.Com's Answer #617761 by ikleyn(52816)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "1.  ln(AB) = ln(A) + ln(B) = x + y.\r
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\n" ); document.write( "\n" ); document.write( "     First equality is the basic property of the logarithm.  Are you familiar with it?\r
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\n" ); document.write( "\n" ); document.write( "     The second equality is true because  ln(A) = x  and  ln(B) = y,  which is given.  I simply made a substitution here.\r
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\n" ); document.write( "\n" ); document.write( "2.  ln(A)/ln(B) = \"x%2Fy\".\r
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\n" ); document.write( "\n" ); document.write( "     Simply substitute  x  and  y  instead of  ln(A)  and  ln(B)  into the numerator and denominator. \r
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\n" ); document.write( "\n" ); document.write( "3.  \"A%2AB\" = \"e%5Ex\" . \"e%5Ey\".\r
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\n" ); document.write( "\n" ); document.write( "     Since  \"ln%28A%29\" = \"x\",  you have  \"A\" = \"e%5Ex\".\r
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\n" ); document.write( "\n" ); document.write( "     Since  \"ln%28B%29\" = \"y\",  you have  \"B\" = \"e%5Ey\".\r
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\n" ); document.write( "\n" ); document.write( "     Then substitute this into  \"A%2AB\".\r
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\n" ); document.write( "\n" ); document.write( "That is all,  my dear.\r
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\n" ); document.write( "\n" ); document.write( "Look into my lessons \r
\n" ); document.write( "\n" ); document.write( "    - WHAT IS the logarithm  \r
\n" ); document.write( "\n" ); document.write( "    - Properties of the logarithm \r
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