document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000186>Question 1000186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I usually know how to do questions involving substitution but this one is really proving difficult \r<BR>\n" );
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document.write( "x/3+y/2=-4<BR>\n" );
document.write( "x-3y=6   \r<BR>\n" );
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document.write( "I tried substituting for the x but I'm not even sure where to go from there  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617737 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/3+y/2=-4<BR>\n" );
document.write( "x-3y=6 <BR>\n" );
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document.write( "Let's begin by getting the fractions out of the way. On the first equation, multiply both sides by 6 (because 6 is a common denominator for 3 and 2):<BR>\n" );
document.write( "x/3+y/2=-4<BR>\n" );
document.write( "6(x/3)+6(y/2)= 6(-4)<BR>\n" );
document.write( "2x+3y= -24 This is now our 1st equation.<BR>\n" );
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document.write( "x-3y= 6 Add 3y on both sides:<BR>\n" );
document.write( "x= 6+3y Now let's substitute this value for x:<BR>\n" );
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document.write( "2(6+3y)+3y= -24<BR>\n" );
document.write( "12+6y+3y= -24 Subtract 12 from both sides and add y on left<BR>\n" );
document.write( "9y= -36 Divide by 9<BR>\n" );
document.write( "y= -4<BR>\n" );
document.write( "And we said that x was:<BR>\n" );
document.write( "x= 6+3y<BR>\n" );
document.write( "x= 6+3(-4)<BR>\n" );
document.write( "x= 6+-12<BR>\n" );
document.write( "x= - 6<BR>\n" );
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document.write( "Proof:<BR>\n" );
document.write( "x/3+y/2=-4<BR>\n" );
document.write( "-6/3+-4/2= -4<BR>\n" );
document.write( "-2+-2= -4 We have the correct answer here. You do the same with the other equation and you'll find we have the correct answer.<BR>\n" );
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document.write( "Now let’s find x:<BR>\n" );
document.write( "x= 6+3(-4)<BR>\n" );
document.write( "x= 6- 12<BR>\n" );
document.write( "x= -6<BR>\n" );
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