document.write( "Question 1000212: The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 40 mph requires 80 ft to stop, find the stopping distance for a car traveling at 65 mph. \n" ); document.write( "
Algebra.Com's Answer #617720 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\"s+%28alpha%29+v%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"+s+++=+k+v%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "80 = k*40^2\r
\n" ); document.write( "\n" ); document.write( "80/1600 = k\r
\n" ); document.write( "\n" ); document.write( "1/20 = k\r
\n" ); document.write( "\n" ); document.write( "Plug k & v\r
\n" ); document.write( "\n" ); document.write( "s = 1/20 * 65^2\r
\n" ); document.write( "\n" ); document.write( "=211.25 ft
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