document.write( "Question 85531: 2x+y=2
\n" ); document.write( "4x+y=4\r
\n" ); document.write( "\n" ); document.write( "If you multiply one of these by -1, the Ys will cancel, enabling you to solve it for x:\r
\n" ); document.write( "\n" ); document.write( "-1(2x + y = 2) --> -2x - y = -2
\n" ); document.write( " 4x + y = 4 --> 4x + y = 4
\n" ); document.write( " -----------
\n" ); document.write( " 2x = 2
\n" ); document.write( " x = 1\r
\n" ); document.write( "\n" ); document.write( "Now plug 1 in for x into either of the original equations to get y:\r
\n" ); document.write( "\n" ); document.write( "2(1) + y = 2 [using the first eqution]
\n" ); document.write( "2 + y = 2
\n" ); document.write( "y = 0
\n" ); document.write( "The solutoin is (1 , 0)
\n" ); document.write( "

Algebra.Com's Answer #61772 by scianci(186)\"\" \"About 
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