document.write( "Question 1000209: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 3960 dollars. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #617700 by mananth(16946)![]() ![]() You can put this solution on YOUR website! investment in 10% --------x \n" ); document.write( "Investment in 6% ----------2x\r \n" ); document.write( "\n" ); document.write( "10%x+6%(2x) = 3960\r \n" ); document.write( "\n" ); document.write( "multiply by 100\r \n" ); document.write( "\n" ); document.write( "10x+12x=396000\r \n" ); document.write( "\n" ); document.write( "22x=396000 \n" ); document.write( "x= 396000/22\r \n" ); document.write( "\n" ); document.write( "x=18000\r \n" ); document.write( "\n" ); document.write( "10000 @ 10% \n" ); document.write( "20,000 @6% \n" ); document.write( " |