document.write( "Question 1000186: I usually know how to do questions involving substitution but this one is really proving difficult \r
\n" ); document.write( "\n" ); document.write( "x/3+y/2=-4
\n" ); document.write( "x-3y=6 \r
\n" ); document.write( "\n" ); document.write( "I tried substituting for the x but I'm not even sure where to go from there
\n" ); document.write( "

Algebra.Com's Answer #617687 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "First Equation
\n" ); document.write( "\"x%2F3%2By%2F2=-4\"
\n" ); document.write( "\"y%2F2=-x%2F3-4\"
\n" ); document.write( "\"y=-%282%2F3%29x-12\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Second Equation
\n" ); document.write( "\"x-3y=6\"
\n" ); document.write( "\"-3y=-x%2B6\"
\n" ); document.write( "\"y=x%2F3-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The system should be solvable.
\n" ); document.write( "Both formulas for y can be shown equated to find a solution.
\n" ); document.write( "\"highlight_green%28-%282%2F3%29x-12=x%2F3-2%29\"----equating the two y expressions
\n" ); document.write( "\"-%282%2F3%29x-12-%281%2F3%29x=-2\"
\n" ); document.write( "\"-x-12=-2\"
\n" ); document.write( "\"x%2B12=-2\"
\n" ); document.write( "\"highlight%28x=-14%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Using the y equivalent of the second equation:
\n" ); document.write( "\"y=x%2F3-2\"
\n" ); document.write( "\"y=14%2F3-2\"
\n" ); document.write( "\"y=14%2F3-6%2F3\"
\n" ); document.write( "\"highlight%28y=8%2F3%29\"
\n" ); document.write( "
\n" );