document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000139>Question 1000139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: BE and AD bisect each other.<BR>\n" );
document.write( "Prove: AB congruent to DE </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617648 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you draw it properly, you will see that you have congruent triangles by SAS.  Once you have that, you know that AB = DE by CPCTC. </SPAN>\n" );
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