document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1000104>Question 1000104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive integers such that the sum of the first two is 13 less than the third </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617596 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the three consecutive integers x, x+1, and x+2.<BR>\n" );
document.write( "Thus<BR>\n" );
document.write( "x + (x+1) = (x+2)-13<BR>\n" );
document.write( "Now solve...<BR>\n" );
document.write( "2x+1=x-11<BR>\n" );
document.write( "x = -12<BR>\n" );
document.write( "Thus the numbers are<BR>\n" );
document.write( "-12, -11, and -10. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );