document.write( "Question 999879: My daughter has a pre-algebra problem she nor I can figure out how to answer. The math problem is asking us to use the 5 step plan to solve it. Here is the written math problem to solve for:
\n" ); document.write( "What are the possible lengths and wideths of arectangle if its length is 8 centimeters longer than the width, and the area is less than or equal to 33 square centimeters?
\n" ); document.write( "a. Identify.
\n" ); document.write( "b. Strategize.
\n" ); document.write( "c. Set up.
\n" ); document.write( "d. Check.\r
\n" ); document.write( "\n" ); document.write( "We both came to the conclusion that since L x W = A that the Width must be 3 and the Length must be 11 because 11 x 3 = 33 since the problem states that the area must be less than or equal to 33 square cm. And since it states that the Length is 8 centimeters longer than the width we know that if 3 is the width then adding 8 to 3 = 11. Only problem is we do not understand how to set this up as an equation to solve through the 5 step plan. How do we do this?
\n" ); document.write( "

Algebra.Com's Answer #617541 by MathTherapy(10552)\"\" \"About 
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My daughter has a pre-algebra problem she nor I can figure out how to answer. The math problem is asking us to use the 5 step plan to solve it. Here is the written math problem to solve for:
\n" ); document.write( "What are the possible lengths and wideths of arectangle if its length is 8 centimeters longer than the width, and the area is less than or equal to 33 square centimeters?
\n" ); document.write( "a. Identify.
\n" ); document.write( "b. Strategize.
\n" ); document.write( "c. Set up.
\n" ); document.write( "d. Check.\r
\n" ); document.write( "\n" ); document.write( "We both came to the conclusion that since L x W = A that the Width must be 3 and the Length must be 11 because 11 x 3 = 33 since the problem states that the area must be less than or equal to 33 square cm. And since it states that the Length is 8 centimeters longer than the width we know that if 3 is the width then adding 8 to 3 = 11. Only problem is we do not understand how to set this up as an equation to solve through the 5 step plan. How do we do this?
\n" ); document.write( "
This is NOT an EQUATION, but an INEQUALITY instead
\n" ); document.write( "Let width be W
\n" ); document.write( "Then length = W + 8
\n" ); document.write( "Area: W(W + 8), or \"W%5E2+%2B+8W\"
\n" ); document.write( "We then get: \"W%5E2+%2B+8W+%3C=+33\"
\n" ); document.write( "\"W%5E2+%2B+8W+-+33+%3C=+0\"
\n" ); document.write( "\"%28W+-+3%29%28W+%2B+11%29+%3C=+0\"
\n" ); document.write( "Width or \"highlight_green%28W+%3C=+3%29\" OR W ≤ - 11 (ignore)\r
\n" ); document.write( "\n" ); document.write( "Thus, if width (W) = 3, then length = 3 + 8, or 11
\n" ); document.write( "If width (W) = 2, then length = 2 + 8, or 10\r
\n" ); document.write( "\n" ); document.write( "In other words, your width MUST BE EQUAL to or less than 3. Whatever value you assign to W, or width, you add 8 to that value to get the length.
\n" ); document.write( "Note that width, or \"W+%3C%3E+0\", or CANNOT be LESS than 0, so the range of values for the width is: \"highlight_green%280+%3C+W+%3C=+3%29\" \n" ); document.write( "
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