document.write( "Question 1000030: 1.A system of linear equations is solved by substitution and results in the equation 0 = 0. This means that the equation has NO solution.
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\n" ); document.write( "\n" ); document.write( "2.A set of twenty-five coins, whose value is P113, consists of 1-peso coins, 5-peso coins and 10-peso coins. If the 1-peso coins were 5-peso coins, the 5-peso coins were 10-peso coins,and the 10-peso coins were 1-peso coins, the total value is also P113. How many 1-peso coins are in the set?
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Algebra.Com's Answer #617535 by ikleyn(52879)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1. The answer is FALSE.\r\n" );
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document.write( "2. Let x = the number of 1-peso coins, \r\n" );
document.write( "       y = the number of 5-peso coins, and\r\n" );
document.write( "       z = the number of 10-peso coins.\r\n" );
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document.write( "Then you have the system of 3 equations with 3 unknowns\r\n" );
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document.write( " x +    y +   z = 25\r\n" );
document.write( " x +   5y + 10z = 113,\r\n" );
document.write( "5x +  10y +   z = 113.\r\n" );
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document.write( "Could you solve this system yourself?\r\n" );
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\n" ); document.write( "Comment from student: X=13,Y=4 AND Z=8 DID I GET IT RIGHT :) ?
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\n" ); document.write( "\n" ); document.write( "Response: Absolutely right. Good job!\r
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