document.write( "Question 1000030:  1.A system of linear equations is solved by substitution and results in the equation 0 = 0. This means that the equation has NO solution.
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document.write( "2.A set of twenty-five coins, whose value is P113, consists of 1-peso coins, 5-peso coins and 10-peso coins.  If the 1-peso coins were 5-peso coins, the 5-peso coins were 10-peso coins,and the 10-peso coins were 1-peso coins, the total value is also P113.   How many 1-peso coins are in the set? \n" );
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| Algebra.Com's Answer #617535 by ikleyn(52879)     You can put this solution on YOUR website! \r\n" ); document.write( "1. The answer is FALSE.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2. Let x = the number of 1-peso coins, \r\n" ); document.write( " y = the number of 5-peso coins, and\r\n" ); document.write( " z = the number of 10-peso coins.\r\n" ); document.write( "\r\n" ); document.write( "Then you have the system of 3 equations with 3 unknowns\r\n" ); document.write( "\r\n" ); document.write( " x + y + z = 25\r\n" ); document.write( " x + 5y + 10z = 113,\r\n" ); document.write( "5x + 10y + z = 113.\r\n" ); document.write( "\r\n" ); document.write( "Could you solve this system yourself?\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------- \n" ); document.write( "Comment from student: X=13,Y=4 AND Z=8 DID I GET IT RIGHT :) ? \n" ); document.write( "--------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Response: Absolutely right. Good job!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |