document.write( "Question 1000014: Some number of dimes plus Nickels equal $7.20 . the number of dimes is three less than twice a number of Nickels how many dimes and nickels are there \n" ); document.write( "
Algebra.Com's Answer #617510 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "N=number of nickels; D=number of dimes=2N-3 \n" ); document.write( ". \n" ); document.write( "$0.05N+$0.10D=$7.20 . This converts number of coins to money value. \n" ); document.write( "$0.05N+$0.10(2N-3)=$7.20 . This substitutes for D. \n" ); document.write( "$0.05N+$0.20N-$0.30=$7.20 \n" ); document.write( "$0.25N=$7.50 \n" ); document.write( "N=30 \n" ); document.write( "ANSWER 1: There are 30 nickels. \n" ); document.write( ". \n" ); document.write( "D=2N-3 \n" ); document.write( "D=2(30)-3 \n" ); document.write( "D=60-3=57 \n" ); document.write( "ANSWER 2: There are 57 dimes. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "$0.05N+$0.10D=$7.20 \n" ); document.write( "$0.05(30)+$0.10(57)=$7.20 \n" ); document.write( "$1.50+$5.70=$7.20 \n" ); document.write( "$7.20=$7.20 \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |