document.write( "Question 1000014: Some number of dimes plus Nickels equal $7.20 . the number of dimes is three less than twice a number of Nickels how many dimes and nickels are there \n" ); document.write( "
Algebra.Com's Answer #617510 by macston(5194)\"\" \"About 
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\n" ); document.write( "N=number of nickels; D=number of dimes=2N-3
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\n" ); document.write( "$0.05N+$0.10D=$7.20 . This converts number of coins to money value.
\n" ); document.write( "$0.05N+$0.10(2N-3)=$7.20 . This substitutes for D.
\n" ); document.write( "$0.05N+$0.20N-$0.30=$7.20
\n" ); document.write( "$0.25N=$7.50
\n" ); document.write( "N=30
\n" ); document.write( "ANSWER 1: There are 30 nickels.
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\n" ); document.write( "D=2N-3
\n" ); document.write( "D=2(30)-3
\n" ); document.write( "D=60-3=57
\n" ); document.write( "ANSWER 2: There are 57 dimes.
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\n" ); document.write( "CHECK:
\n" ); document.write( "$0.05N+$0.10D=$7.20
\n" ); document.write( "$0.05(30)+$0.10(57)=$7.20
\n" ); document.write( "$1.50+$5.70=$7.20
\n" ); document.write( "$7.20=$7.20
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