document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=999783>Question 999783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let 2^a = 6 and 2^b = 7. Using exponent rules, solve the equation in terms of a and b.<BR>\n" );
document.write( "7^x = 1/32<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #617420 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=617420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 2^a = 6 and 2^b = 7. Using exponent rules, solve the equation in terms of a and b.<BR>\n" );
document.write( "7^x = 1/32<BR>\n" );
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document.write( "2^b = 7<BR>\n" );
document.write( "7^x = 2^(bx) = 1/32 = 2^(-5)<BR>\n" );
document.write( "bx = -5<BR>\n" );
document.write( "x = -5/b<BR>\n" );
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